Switch Builder

I had to write a switch case for an Enum that contains huge amount of members. Writing each case with hitting the keyword is frustrating and time consuming. So I wrote a little code that builds a switch case for every member of Enum in an Assembly.

The Logic behind the scene is extremely simple. What one need to do is.

• load an assembly
• Enumerate all Enum types from the loaded assembly.
• Build the switch case

Load and Enumerat all Enums from an assembly and store it in a combo box

private void LoadAsm(String Path)

{

/*Load an Assembly*/

Assembly asm = Assembly.LoadFile(Path);

if (asm != null)

{

Type[] tp = asm.GetTypes();

foreach (Type t in tp)

{

/*If type is Enum add it to tne combobox*/

if (t.IsEnum && t.BaseType == typeof(Enum))

{

this.comboBox1.Items.Add(t);

}

}

}

}

Now, All enums are loaded into combobox. Time to build the switch case

private void BuildSwitch()

{

Type t = this.comboBox1.SelectedItem as Type;

StringBuilder sb = new StringBuilder();

sb.AppendLine(String.Format(“{0} Enm;”, t.Name));

sb.AppendLine(“switch(Enm)”);

sb.AppendLine(“{“);

/*Prepare case for each name of the enum*/

foreach (string str in Enum.GetNames(t))

{

sb.AppendLine(string.Format(“case {0}.{1}:”, t.Name,str));

sb.AppendLine(“break;”);

}

sb.AppendLine(“}”);

this.richTextBox1.Text = sb.ToString();

}

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